How do you graph x^2+y^2=25? - Socratic
Jul 1, 2018 · Below The general formula of a circle is given by: (x-h)^2+(y-k)^2=r^2 where (h,k) is the centre is r is the radius Therefore, x^2+y^2=25 can also be written as (x-0)^2+(y-0)^2=5^2 We can immediately see that the centre is (0,0) and the radius is 5 The graph is drawn below graph{x^2+y^2=25 [-10, 10, -5, 5]}
How do you graph #x^2 + y^2 = 1 - Socratic
Jan 25, 2016 · It is the equation of a circle: Probably you can recognize it as the equation of a circle with radius r=1 and center at the origin, (0,0): The general equation of the circle of radius r and center at (h,k) is: (x-h)^2+(y-k)^2=r^2
What is the polar form of x^2 + y^2 = 2x? | Socratic
Nov 12, 2014 · x^2+y^2=2x, which looks like: by plugging in {(x=rcos theta),(y=rsin theta):}, => (rcos theta)^2+(r sin theta)^2=2rcos theta by multiplying out, => r^2cos^2theta+r^2sin^2theta=2rcos theta by factoring out r^2 from the left-hand side, => r^2(cos^2theta+sin^2theta)=2rcos theta by cos^2theta+sin^2theta=1, => r^2=2rcos theta by …
How do you graph x^2 + y^2 = 16? | Socratic
Mar 13, 2018 · Given: x^2+y^2=16 Note that we can rewrite this equation as: (x-0)^2+(y-0)^2 = 4^2 This is in the standard form: (x-h)^2+(y-k)^2 = r^2 of a circle with centre (h, k) = (0, 0) and radius r = 4 So this is a circle of radius 4 centred at the origin: graph{x^2+y^2 = 16 [-10, 10, -5, 5]}
How do you graph x^2+y^2=4? - Socratic
Feb 28, 2016 · See the explanantion This is the equation of a circle with its centre at the origin. Think of the axis as the sides of a triangle with the Hypotenuse being the line from the centre to the point on the circle. By using Pythagoras you would end up with the equation given where the 4 is in fact r^2 To obtain the plot points manipulate the equation as below: Given:" "x^2+y^2=r^2" …
How do you graph x=y^2-2y? - Socratic
Feb 12, 2018 · See below: Let's first notice that the graph is going to have a parabolic shape. Since the parabolic portion of the equation is in y and not in x, the graph itself is going to be "sideways". We can chart out a few values to see what it's going to look like. It might be easier to look at y values first and then find the resulting x: ((y,x),(0,0),(1,-1),(-1,3),(2,0),(-2,8),(3,3)) …
How do you sketch #f(x,y) = ln(x^2+y^2)#? - Socratic
Feb 23, 2015 · Hello, Let mathcal(S) the surface of equation z = ln(x^2+y^2) : it's the graph of your function f. Remark that mathcal(S) is a revolution surface, because f(x,y) = g(r) where r = sqrt(x^2+y^2) is the polar radius. Actually, g(r) = ln(r^2) = 2 ln(r). So, graph the curve of equation z = 2ln(x) in the xOz plane. You get : Finally, rotate this curve around the Oz axis. You get …
How do you sketch the graph of #y=x^2-2x# and describe the
Jun 9, 2017 · What we are transforming is the basis of #y=x^2# where #x_("vertex")=0# Let the vertex of #y=x^2->(x_1,y_1)=(0,0)# Note this is the same as: #y=x^2+0x+0# Note that the y-intercept is at #x=0# So for this case the y-intercept is #y=(0)^2+0x+0=0# #color(blue)("Transformation left or right - Shift left or right")# Let the vertex of #y=x^2-2x ->(x ...
How do you graph the line y=-x+2? + Example - Socratic
Mar 7, 2016 · The equation #y=x# is saying: whatever value you decide to give to #x# will also end up being the same value for #y# Notice that the graph goes upwards as you move from left to right This is called a positive slope (gradient) If it had been #y=-x# then the slope would go down as you move from left to right. '~~~~~ This is what happens when the ...
How do you graph x^2+y^2=9 and what are its lines of symmetry ...
Apr 27, 2017 · This is the standard form for the graph of a circle! (x-h)^2+(y-k)^2=r^2 Doesn't a circle have infinitely many lines of symmetry? Let's look at the graph... its center will be at (0,0), and the radius = 3. Imagine any line drawn through the center will "split" the circle in half, and can be called a line of symmetry.