Aug 6, 2011 · I am sorry, I just don't follow it that well. Why does there HAVE to be a point C whose gradient is equal to the gradient of the secant AB?

Apr 26, 2016 · Prove that sinA·sinB <= sin^2(C/2) Discuss the case of equality. My attempt : I used Apollonius' Theorem to get -> a^2 + b^2 = 2(BD)c {where a, b, c are sides opposite to angle A, B, C respectively in triangle ABC.} and tried to get the result using the triangle inequalities and Sine Law but couldn't figure out the way to use them to get the ...

Oct 9, 2009 · - If A, B, C are the angles of a triangle; show that i) (tan A - cot B) = cos C sec A csc B. ii) sin 2A + sin 2B + sin 2C = 4 sin A sin B sin C

Aug 21, 2010 · High School Math Help High School STEM University Math Homework Help University STEM General Mathematics Search forums

Aug 6, 2011 · I must admit that I am a little confused. How does B-A = QB-PA? You seem to subtract these segments horizontally, but then you subtract PS from QM vertically. Point Q lies on the curve y=x. the perpendicular dropped from Q on the x-axis meets the x-axis at B. hence OB=QB. Now OB=measure of...

Aug 7, 2011 · y = r sina sinb z = cosa thus I get r(a,b) = (sina cosb, sina sinb, cosa). I set r = 1 as I am only intrested in the surface so integration over r would "fill" the sphere and that would be volume rather than surface. (This is my assumption) dr/da x dr/db = (sin^2a*cosb,sin^2a*sinb,sina*cosa)

Jan 18, 2010 · Using Lagrange Mean Value Theorem prove that for every a,b are real numbers on has |sina-sinb|

Feb 2, 2011 · hello there iwas wandering if someone out there could help me. i have been given a problem and i am really struggling to resolve a solution if sin A + sin B = X cos A + cos B = y then prove sin (A+B)= (2xy)/(x^2+y^2) if you can help thankyou i have been trying to use the formula a …

Nov 3, 2012 · High School Math Help High School STEM University Math Homework Help University STEM General Mathematics Search forums

Dec 6, 2007 · Hello, bsothe1! If we are allowed the Sum-to-Product identities, it's easy.. . \sin A + \sin B \:=\:2\sin\!\left(\frac{A+B}{2}\right)\cos\!\left(\frac{A-B}{2}\right)