java.util.scanner - How can I read input from the console using the ...
WEBHow could I read input from the console using the Scanner class? Something like this: System.out.println("Enter your username: "); Scanner = input(); // Or something like this, I don't know the code Basically, all I want is have the scanner read an input for the username, and assign the input to a String variable.
Validating input using java.util.Scanner - Stack Overflow
WEBExample 1: Validating positive ints. Here's a simple example of using hasNextInt() to validate positive int from the input. Scanner sc = new Scanner(System.in); int number; do {. System.out.println("Please enter a positive number!"); while (!sc.hasNextInt()) {. System.out.println("That's not a number!"); sc.next(); // this is important!
java - Take a char input from the Scanner - Stack Overflow
WEBDec 19, 2012 · String input=key.next(); // you can also write key.nextLine to take a String with spaces also. char firstChar=input.charAt(0); char charAtAnyPos= input.charAt(pos); // in pos you enter that index from where you want to get the char from. By the way, you can't take a char directly as an input.
java - How to put a Scanner input into an array... for example a …
WEBMay 8, 2010 · 28. Scanner input = new Scanner(System.in); double[] numbers = new double[5]; for (int i = 0; i < numbers.length; i++) System.out.println("Please enter number"); numbers[i] = input.nextDouble(); This won't work when you go over the array capacity (5). A better option would be to use a List.
What does Scanner input = new Scanner(System.in) actually mean?
WEBJun 3, 2015 · Scanner input = new Scanner (System.in); it creates a new Scanner instance which points to the input stream passed as argument. So here the steam is Standard input stream. So, once your scanner instance is pointing to it, you can scan the stream and store the value into integers, strings and do other things.
Java Scanner String input - Stack Overflow
WEBMar 22, 2012 · If you use the nextLine() method immediately following the nextInt() method, nextInt() reads integer tokens; because of this, the last newline character for that line of integer input is still queued in the input buffer and the next nextLine() will be reading the remainder of the integer line (which is empty).
How to use Scanner to accept only valid int as input
WEBUse Scanner.hasNextInt (): Returns true if the next token in this scanner's input can be interpreted as an int value in the default radix using the nextInt () method. The scanner does not advance past any input. Here's a snippet to illustrate: Scanner sc = new Scanner (System.in); System.out.print ("Enter number 1: "); while (!sc.hasNextInt ...
java - Scanner error with nextInt () - Stack Overflow
WEBOct 11, 2012 · The problem is you are called nextInt() which reads the next integer from the stream that the Scanner object points to, if there is no integer there to read (i.e. if the input is exhausted then you will see that NoSuchElementException) From the JavaDocs, the nextInt() method will throw these exceptions under these conditions: You can fix this ...
Scanner is skipping nextLine() after using next() or nextFoo()?
WEBAug 14, 2011 · Workaround: Either put a Scanner.nextLine call after each Scanner.nextInt or Scanner.nextFoo to consume the rest of that line including newline: int option = input.nextInt (); input.nextLine (); // Consume left over newline String str1 = input.nextLine (); Or, even better, read the input through Scanner.nextLine and convert your input to the ...
Java If else Statement on String value, with Scanner input
WEBAug 29, 2018 · In this program i need to input word(s), i.e., alphabet character that has been assigned to be the values of the String data type. So that the program will print the sequential if statement, but is seems that program is not recognizing the input, because it keep printing only else statement.