How do you evaluate #sec(pi)#? - Socratic
WEBMay 25, 2016 · 1 Answer. sec(π) = 1 cos(π) Now you use this trivial identity: cos(π) = (−1) = 1 −1 ⇒ Refine = −1.
How do I find the value of #sec(-pi)#? - Socratic
WEBSep 6, 2015 · Help. sec (-pi) = -1 Using a unit circle in standard position, the angle (-pi) is a semicircle with its terminal point on the negative X-axis (at (x,y) = -1,0) The length of the hypotenuse will be color (white) ("XXX")sqrt ( (-1)^2+0^2) = 1 and since the definition of sec is color (white) ("XXX")sec = ("hypotenuse")/ ("x-coordinate") (of unit ...
Sec^2 (π/4) - Socratic
WEBMar 7, 2018 · 24330 views around the world You can reuse this answer ...
How do you find the exact value of #sec(pi/12)#? - Socratic
WEBFeb 13, 2018 · See below. We know that secx= 1/cosx. Therefore: sec(pi/12)= 1/cos(pi/12) We know that pi/12 = pi/3 - pi/4. Thus cos(pi/12) = cos(pi/3 - pi/4) The difference formula ...
What is the sec of pi/4? - Socratic
WEBOct 20, 2015 · sec(pi/4)=1 An angle of pi/4 can be represented as a standard triangle with adjacent and opposite side ...
Why does sec(pi/4)= sqrt2? - Socratic
WEBSep 23, 2015 · Why does sec (pi/4) = sqrt2 sec ((pi)/4) = 1/(cos (pi/4)) Trig Table of Special arcs gives --> cos (pi/4) = sqrt2/2.
How do you evaluate #sec(pi/9)#? - Socratic
WEBFeb 8, 2015 · 1 Answer. Alternate Method. I think the question is using known trigonometric identities. As π 3 ⋅ 1 3 = π 9 we can compute sec(π 9) using cos(π 3). Solving the equation results in 3 roots. x = cosθ = (−0.76604, −0.17365,0.93969) as the angle is less than π 2 cosine is positive. Hence choose the positive root.
How do I find the value of sec pi/12? - Socratic
WEBOct 17, 2015 · sec(π 12) = 1 cosa = 2 √2 + √3. √2 +√3 2 = 1.93 2 = 0.97. OK. Find: sec (pi/12) sec (pi/12) = 1/ (cos pi/12). Find cos (pi/12). Call cos (pi/12) = cos a --> cos 2a = cos ( (2pi)/12) = cos (pi/6) = sqrt3/2 Apply the trig identity: cos 2a = 2cos^2 a - 1. cos 2a = sqrt3/2 = 2cos^2 a - 1 cos^2 a = 1 = sqrt3/2 = (2 + sqrt3)/2 2cos^2 a = (2 ...
How do you evaluate #sec(pi/3)#? - Socratic
WEBApr 4, 2016 · 2 > secx = 1/cosx rArr sec(pi/3) = 1/cos(pi/3) Using the pi/3 , pi/6 , pi/2 " triangle " with sides of length 1 ,sqrt3 " and " 2 we can obtain the exact value of cos(pi/3) = 1/2 rArr sec(pi/3) = 1/(1/2) = 2
How do you evaluate #sec^-1(2)#? - Socratic
WEBAug 13, 2016 · sec^{-1}(2) = pi/3 Let the answer be x. Since sec^{-1}(2) = x, sec(x) = 2. As secant is the reciprocal of the cosine function, i.e. sec(x) = 1/cos(x), the following must be true as well. 1/cos(x) = 2 Or cos(x) = 1/2. The range of sec^{-1}(x) is [0,pi/2) uu (pi/2,pi]. The range of cos^{-1}(x) is [0,pi]. Since the ranges are similar, we can find ...