elementary number theory - Show that …
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Simplifying large exponents in modular arithmetic like $1007$ in …
Sep 12, 2013 · I was simplifying a larger modular arithmetic problem ($2013^{2014} \pmod{5}$) and got it down to $4^{1007} \pmod{5}$ and am wondering if there's a general approach to …
elementary number theory - $a^ {37} \equiv a \pmod {1729 ...
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CCRT = Constant case CRT: - Mathematics Stack Exchange
Nov 9, 2016 · Your proof is correct. It invokes a simple special case of CRT = Chinese Remainder Theorem when the values $\,a_1 = a_2\,$ are constant, say $\,a,\,$ which is equivalent to the …
Prove that if $a\equiv b \pmod m - Mathematics Stack Exchange
Jun 12, 2017 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …
elementary number theory - Prove $a^{pq} \equiv a \pmod {pq ...
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …
elementary number theory - Mathematics Stack Exchange
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …
Calculating $1819^{13} \\pmod{2537}$ using Fermat's little theorem
Since $1819^{2} = 513\pmod{2537}$ if we raise each side to power $4$ we get $1819^{8} = 513^{4}\pmod{2537}$ which is what you have asked. The idea of using powers of $2$ is that …
Find all four solutions to $x^2 \\equiv 133 \\pmod {143}$
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modular arithmetic - How to solve congruence $x^y = a \pmod p ...
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …