
What is the antiderivative of 9/x^3? - Socratic
Jul 7, 2016 · int 9/x^3 d x=-9/(2x^2)+C int 9/x^3 d x int 9/x^3 d x=9 int (d x)/x^3 int 9/x^3 d x=9 int x^(-3) d x "now use power rule" int 9/x^3 d x=9 [1/(-3+1)x^(-3+1)] int 9/x^3 ...
How do you solve |x - 3| < 9? - Socratic
Apr 2, 2017 · See the entire solution process below: The absolute value function takes any negative or positive term and transforms it to its positive form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent. -9 < x - 3 < 9 Add color(red)(3) to each segment of the system of inequalities to solve for x while keeping the …
How do you solve #9(x+3)=27# using the distributive property?
Aug 23, 2016 · x=0 9(x+3)=27 or x+3=27/9 or x+3=3 or x=3-3 or x=0
Resolver la Ecuación x-9=3 - Respuesta - Cymath
\[x-9=3\] +. > < ...
What is the square root of 9x^3? - Socratic
Sep 25, 2015 · =color(blue)(3xsqrtx sqrt(9x^3) can be written as: sqrt(3^2 *color(blue)(x^2*x) =color(blue)(3 *x) sqrt x =color(blue)(3xsqrtx
How do you integrate int (x+5)/sqrt (9-(x-3)^2) dx? - Socratic
Aug 4, 2016 · 8sin^(-1)((x-3)/3) - sqrt(9-(x-3)^2) + C I hope you like substitutions, because we're about to do a lot of them. To start, let u = x-3 implies du = dx Integral becomes: int (u+8)/(sqrt(9-u^2)) du Now we want to deal with the denominator. This type of function will often involve a trig substitution - if you learn/can derive the pythagorean identities they are very helpful in figuring …
Is f(x)=(x^2-9)/(x-3) continuous at x=3? - Socratic
Dec 7, 2016 · Thus, f(x) is not continuous at x=3. Bonus: Here's a tip to determine where some functions will be discontinuous. Any x-value that makes any denominator in the function equal to 0 is a point of discontinuity. So for the function above, x-3=0 when x=3, and so the function will be discontinuous at x=3.
Solve the Equation x-3=9 - Answer | Math Problem Solver - Cymath
Solve the Equation x-3=9 - Answer | Math Problem Solver - Cymath ... \\"Get
How do you find the Limit of #sqrt(x^2 - 9) / (x - 3) # as x
Sep 25, 2016 · (I am assuming that we want to stay in the real numbers.) As xrarr3^-, the numerator is approaching 6 and the denominator is a positive number approaching 0. As xrarr3^-, the ratio is increasing without bound. lim_(xrarr3^-) sqrt(x^2-9)/(x-3) = lim_(xrarr3^-) (x+3)/sqrt(x^2-9) =oo
How do you evaluate log_9 x=3/2? - Socratic
Oct 27, 2016 · x=27 Remember that in general log_b a = c means b^c=a (You really need to memorize this; it's a basic definition.)