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youtube.com > Jatin Gupta
n^logn, log(n!), (log n)! , 2^n , sqrt(n) | Arrange the function in increasing asymptotic order
YouTube · Jatin Gupta · 2K views · Oct 5, 2022
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Arrange the functions √(n), 1000 logn, n logn, 2 n !, 2^n, 3^n and n^2 ...
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Solved If f(n)=nlogn+100n−logn and g(n)=n2−10000n then | Chegg.com
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Solved 13) Select the function that is θ(nlogn). a. | Chegg.com

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Solved logn!=θ(nlogn) | Chegg.com
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Solved logn" is ?(?) (A) n (B) log n 8. (C) n log n (D) log | Chegg.com
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Solved 10. 1 (log n) logn (log )0 n/logn (log n) | sloga n | | Chegg.com

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SOLVED: 'Show that log n! is O(n logn)'
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