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X Y 0
Graph
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X 0
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M6
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2X
1 X
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1 Over X
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2Y 4 Graph
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1 X
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Dy/
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1/X
0
≤ Y ≤ 2X
X − 1 X
− 2 0 Graphically
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1
F(X
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Y 3X 1
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E
X 0
Initial Value
Problem
Why Does X to the Power of
0 Equal 1
Absolute Value
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X
≤ 8
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X
3 0
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Y=
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1/X
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1EX
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1/X
4 4X
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X
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